Question Number 190760 by 073 last updated on 10/Apr/23
Answered by mehdee42 last updated on 10/Apr/23
$$\frac{\mathrm{1}}{\mathrm{2}{log}_{{x}} \mathrm{2}}×\frac{\mathrm{1}}{{log}_{{x}} \mathrm{3}}=\frac{\mathrm{1}}{{log}_{{x}} \mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}{log}_{{x}} \mathrm{3}} \\ $$$$\Rightarrow{lg}_{{x}} \mathrm{18}=\mathrm{1}\Rightarrow{x}=\mathrm{18} \\ $$