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Question-125424




Question Number 125424 by joki last updated on 11/Dec/20
Answered by bramlexs22 last updated on 11/Dec/20
∫ ((d(x^2 +1))/(2(x^2 +1)^2 )) = (1/2)∫ (x^2 +1)^(−2) d(x^2 +1)  = −(1/(2(x+1))) + c
$$\int\:\frac{{d}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}{\mathrm{2}\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} }\:=\:\frac{\mathrm{1}}{\mathrm{2}}\int\:\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{−\mathrm{2}} {d}\left({x}^{\mathrm{2}} +\mathrm{1}\right) \\ $$$$=\:−\frac{\mathrm{1}}{\mathrm{2}\left(\boldsymbol{{x}}+\mathrm{1}\right)}\:+\:\boldsymbol{{c}}\: \\ $$
Answered by Ñï= last updated on 11/Dec/20

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