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Question-190960




Question Number 190960 by pascal889 last updated on 15/Apr/23
Commented by Rasheed.Sindhi last updated on 15/Apr/23
(√(x^2 +3x−28)) +(√(x^2 −2x−8)) =(√(6x^2 −11x−52))     ?
$$\sqrt{{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{28}}\:+\sqrt{{x}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{8}}\:=\sqrt{\mathrm{6}{x}^{\mathrm{2}} −\mathrm{11}{x}−\mathrm{52}}\:\:\:\:\:? \\ $$
Commented by pascal889 last updated on 15/Apr/23
yes sir its 6x^2
$${yes}\:{sir}\:{its}\:\mathrm{6}{x}^{\mathrm{2}} \\ $$
Commented by Frix last updated on 15/Apr/23
If it′s (√(x^2 −3x...)) there′s no real solution  Maybe check before posting?
$$\mathrm{If}\:\mathrm{it}'\mathrm{s}\:\sqrt{{x}^{\mathrm{2}} −\mathrm{3}{x}…}\:\mathrm{there}'\mathrm{s}\:\mathrm{no}\:\mathrm{real}\:\mathrm{solution} \\ $$$$\mathrm{Maybe}\:\mathrm{check}\:\mathrm{before}\:\mathrm{posting}? \\ $$
Commented by pascal889 last updated on 15/Apr/23
nope it x^(2 ) + 3x...
$${nope}\:{it}\:{x}^{\mathrm{2}\:} +\:\mathrm{3}{x}… \\ $$

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