Question Number 191405 by Mingma last updated on 23/Apr/23
Commented by mr W last updated on 23/Apr/23
$${r}=\frac{{ab}}{\:\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }+\left(\mathrm{1}+\sqrt{\mathrm{3}}\right){a}+\mathrm{2}{b}} \\ $$$${with}\:{a}=\mathrm{3},\:{b}=\mathrm{4}: \\ $$$${r}=\frac{\mathrm{12}}{\:\mathrm{16}+\mathrm{3}\sqrt{\mathrm{3}}}\approx\mathrm{0}.\mathrm{566} \\ $$
Commented by mr W last updated on 23/Apr/23
Commented by Mingma last updated on 23/Apr/23
Excellent, sir!