Question Number 126534 by mohammad17 last updated on 21/Dec/20
Commented by mohammad17 last updated on 21/Dec/20
$$?? \\ $$
Answered by mr W last updated on 21/Dec/20
$$\left.\mathrm{1}\right) \\ $$$${C}_{\mathrm{3}} ^{\mathrm{18}} ×{C}_{\mathrm{4}} ^{\mathrm{15}} ×{C}_{\mathrm{6}} ^{\mathrm{11}} =\mathrm{514}\:\mathrm{954}\:\mathrm{080} \\ $$$$ \\ $$$$\left.\mathrm{2}\right) \\ $$$$−{M}−{C}−{T}− \\ $$$$\mathrm{3}!×{P}_{\mathrm{3}} ^{\mathrm{4}} =\mathrm{144} \\ $$$$ \\ $$$$\left.\mathrm{3}\right) \\ $$$$\mathrm{4}^{\mathrm{3}} −\mathrm{1}=\mathrm{63} \\ $$
Answered by benjo_mathlover last updated on 22/Dec/20
$$\left(\mathrm{2}\right)\:\underset{\mathrm{1}^{{st}} } {−}\overset{{E}} {−}\underset{\mathrm{2}^{{nd}} } {\overset{{x}} {−}}\overset{{A}} {−}\underset{\mathrm{3}^{{rd}} } {\overset{{x}} {−}}\overset{{O}} {−}\underset{\mathrm{4}^{{th}} } {−}\:=\:\mathrm{3}!×\mathrm{3}!×\begin{pmatrix}{\mathrm{4}+\mathrm{1}−\mathrm{1}}\\{\:\:\:\:\:\:\:\mathrm{1}}\end{pmatrix} \\ $$$$=\mathrm{6}×\mathrm{6}×\mathrm{4}=\mathrm{144} \\ $$