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Question-61569




Question Number 61569 by Tawa1 last updated on 04/Jun/19
Commented by tanmay last updated on 04/Jun/19
Commented by tanmay last updated on 04/Jun/19
∠CDP=x  ∠EDP=26  DP∥  BC and DP∥ EF
$$\angle{CDP}={x}\:\:\angle{EDP}=\mathrm{26} \\ $$$${DP}\parallel\:\:{BC}\:{and}\:{DP}\parallel\:{EF} \\ $$
Commented by Tawa1 last updated on 04/Jun/19
God bless you sir
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$
Answered by tanmay last updated on 04/Jun/19
x+y=360^o   x+26^o =75^o    x=49   y=311^o
$${x}+{y}=\mathrm{360}^{{o}} \\ $$$${x}+\mathrm{26}^{{o}} =\mathrm{75}^{{o}} \:\:\:{x}=\mathrm{49}\:\:\:{y}=\mathrm{311}^{{o}} \\ $$

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