Question Number 61692 by Tony Lin last updated on 06/Jun/19
$${if}\frac{\mathrm{3}}{\mathrm{2}}\leqslant{x}\leqslant\mathrm{5}, \\ $$$${prove}:\mathrm{2}\sqrt{{x}+\mathrm{1}}+\sqrt{\mathrm{2}{x}−\mathrm{3}}+\sqrt{\mathrm{15}−\mathrm{3}{x}}<\mathrm{2}\sqrt{\mathrm{19}} \\ $$