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Question Number 62244 by Rasheed.Sindhi last updated on 18/Jun/19
Find out x,y, such that gcd(x^3 ,y^2 )=gcd(x^2 ,y^3 )
$$\mathrm{Find}\:\mathrm{out}\:\mathrm{x},\mathrm{y},\:\mathrm{such}\:\mathrm{that} \\ $$$$\:\:\:\:\:\:\mathrm{gcd}\left(\mathrm{x}^{\mathrm{3}} ,\mathrm{y}^{\mathrm{2}} \right)=\mathrm{gcd}\left(\mathrm{x}^{\mathrm{2}} ,\mathrm{y}^{\mathrm{3}} \right) \\ $$
Commented by mr W last updated on 18/Jun/19
one solution is: x=Πp_i ^n_i y=Πq_j ^m_j with p,q=prime number and p≠q
$${one}\:{solution}\:{is}: \\ $$$${x}=\Pi{p}_{{i}} ^{{n}_{{i}} } \\ $$$${y}=\Pi{q}_{{j}} ^{{m}_{{j}} } \\ $$$${with}\:{p},{q}={prime}\:{number}\:{and}\:{p}\neq{q} \\ $$
Commented by Rasheed.Sindhi last updated on 19/Jun/19
Thanks Sir! Waiting for solutions when x & y are noncoprime with some workings.
$$\mathcal{T}{hanks}\:\mathcal{S}{ir}!\: \\ $$$${Waiting}\:{for}\:{solutions}\:\mathrm{w}{hen}\:{x}\:\&\:{y}\:{are} \\ $$$$\:\:{noncoprime}\:{with}\:{some}\:{workings}. \\ $$
Commented by Rasheed.Sindhi last updated on 23/Jun/19
The question having no market value!
$$\mathcal{T}{he}\:{question}\:{having}\:{no}\:{market}\:{value}! \\ $$
Answered by Rasheed.Sindhi last updated on 21/Jun/19
x=Πp_i ^a_i y=Πp_i ^b_i : p_i ∈P ∧ a_i ,b_i ∈W gcd(x^3 ,y^2 )=gcd(x^2 ,y^3 ) ⇒gcd( (Πp_i ^a_i )^3 ,(Πp_i ^b_i )^2 )=gcd( (Πp_i ^a_i )^2 ,(Πp_i ^b_i )^3 ) ⇒gcd( Πp_i ^(3a_i ) , Πp_i ^(2b_i ) )=gcd( Πp_i ^(2a_i ) , (Πp_i ^(3b_i ) ) ⇒Πp_i ^(min(3a_i , 2b_i )) =Πp_i ^(min(2a_i , 3b_i )) ⇒min(3a_i , 2b_i )=min(2a_i , 3b_i ) Possibilities: A: 3a_i >2b_i ∧ { ((2a_i >3b_i ...(i))),((2a_i =3b_i ...(ii))),((2a_i <3b_i ...(iii))) :} B: 3a_i =2b_i ∧ { ((2a_i >3b_i ...(i))),((2a_i =3b_i ...(ii))),((2a_i <3b_i ...(iii))) :} _ C: 3a_i <2b_i ∧ { ((2a_i >3b_i ...(i))),((2a_i =3b_i ...(ii))),((2a_i <3b_i ...(iii))) :} A(i): 3a_i >2b_i ∧ 2a_i >3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒2b_i =3b_i ⇒b_i =0 A(ii): 3a_i >2b_i ∧ 2a_i =3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒2b_i =3b_i =2a_i ⇒a_i =b_i =0 A(iii): 3a_i >2b_i ∧ 2a_i <3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒2b_i =2a_i ⇒a_i =b_i B(i): 3a_i =2b_i ∧ 2a_i >3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒3a_i =2b_i =3b_i ⇒a_i =b_i =0 B(ii): 3a_i =2b_i ∧ 2a_i =3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒3a_i =2b_i =2a_i =3b_i ⇒a_i =b_i =0 B(iii): 3a_i =2b_i ∧ 2a_i <3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒3a_i =2b_i =2a_i ⇒a_i =b_i =0 C(i): 3a_i <2b_i ∧ 2a_i >3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒3a_i =3b_i ⇒a_i =b_i C(ii): 3a_i <2b_i ∧ 2a_i =3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒3a_i =2a_i =3b_i ⇒a_i =b_i C(iii): 3a_i <2b_i ∧ 2a_i <3b_i min(3a_i , 2b_i )=min(2a_i , 3b_i ) ⇒3a_i =2a_i ⇒a_i =0 Possible conditions for exponents of prime factors of x & y (i) a_i =0 : x contain/s factor/s p_i ^0 while y cotain/s p_i ^m where m∈W. For simple example x= p_i ^0 =1& y=p_i ^m gcd((1)^3 ,(p_i ^m )^2 )=gcd((1)^2 ,(p_i ^m )^3 )=1 (ii) b_i =0/a_i =b_i =0 : Similar explanation (iii) a_i =b_i :x & y both contain p_i ^k Any combination of these conditions can be applied. For an example Solution: x=Πp_i ^0 ×Πp_j ^m_j ×Πp_k ^n_k y=Πp_i ^l_i ×Πp_j ^0 ×Πp_k ^n_k
$$\mathrm{x}=\Pi{p}_{{i}} ^{{a}_{{i}} } \:\:\:\mathrm{y}=\Pi{p}_{{i}} ^{{b}_{{i}} } \::\:\:\:\:{p}_{{i}} \in\mathbb{P}\:\:\wedge\:\:{a}_{{i}} ,{b}_{{i}} \in\mathbb{W} \\ $$$$\:\:\mathrm{gcd}\left(\mathrm{x}^{\mathrm{3}} ,\mathrm{y}^{\mathrm{2}} \right)=\mathrm{gcd}\left(\mathrm{x}^{\mathrm{2}} ,\mathrm{y}^{\mathrm{3}} \right) \\ $$$$\:\Rightarrow\mathrm{gcd}\left(\:\left(\Pi{p}_{{i}} ^{{a}_{{i}} } \right)^{\mathrm{3}} ,\left(\Pi{p}_{{i}} ^{{b}_{{i}} } \right)^{\mathrm{2}} \right)=\mathrm{gcd}\left(\:\left(\Pi{p}_{{i}} ^{{a}_{{i}} } \right)^{\mathrm{2}} ,\left(\Pi{p}_{{i}} ^{{b}_{{i}} } \right)^{\mathrm{3}} \right) \\ $$$$\:\Rightarrow\mathrm{gcd}\left(\:\Pi{p}_{{i}} ^{\mathrm{3}{a}_{{i}} } \:,\:\Pi{p}_{{i}} ^{\mathrm{2}{b}_{{i}} } \right)=\mathrm{gcd}\left(\:\Pi{p}_{{i}} ^{\mathrm{2}{a}_{{i}} } ,\:\left(\Pi{p}_{{i}} ^{\mathrm{3}{b}_{{i}} } \right)\right. \\ $$$$\Rightarrow\Pi{p}_{{i}} ^{\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)} =\Pi{p}_{{i}} ^{\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right)} \\ $$$$\:\Rightarrow\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$${Possibilities}: \\ $$$$\:\:\:\:\:{A}:\:\:\:\:\mathrm{3}{a}_{{i}} >\mathrm{2}{b}_{{i}} \:\:\wedge\:\begin{cases}{\mathrm{2}{a}_{{i}} >\mathrm{3}{b}_{{i}} …\left({i}\right)}\\{\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} …\left({ii}\right)}\\{\mathrm{2}{a}_{{i}} <\mathrm{3}{b}_{{i}} …\left({iii}\right)}\end{cases} \\ $$$$\:\:\:\:\:{B}:\:\:\:\:\mathrm{3}{a}_{{i}} =\mathrm{2}{b}_{{i}} \:\wedge\:\begin{cases}{\mathrm{2}{a}_{{i}} >\mathrm{3}{b}_{{i}} …\left({i}\right)}\\{\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} …\left({ii}\right)}\\{\mathrm{2}{a}_{{i}} <\mathrm{3}{b}_{{i}} …\left({iii}\right)}\end{cases} \\ $$$$\:_{} \:\:\:\:{C}:\:\:\:\mathrm{3}{a}_{{i}} <\mathrm{2}{b}_{{i}} \:\wedge\begin{cases}{\mathrm{2}{a}_{{i}} >\mathrm{3}{b}_{{i}} …\left({i}\right)}\\{\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} …\left({ii}\right)}\\{\mathrm{2}{a}_{{i}} <\mathrm{3}{b}_{{i}} …\left({iii}\right)}\end{cases} \\ $$$$ \\ $$$${A}\left({i}\right):\:\:\mathrm{3}{a}_{{i}} >\mathrm{2}{b}_{{i}} \:\:\wedge\:\mathrm{2}{a}_{{i}} >\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\:\:\:\:\:\Rightarrow\mathrm{2}{b}_{{i}} =\mathrm{3}{b}_{{i}} \Rightarrow{b}_{{i}} =\mathrm{0} \\ $$$${A}\left({ii}\right):\:\mathrm{3}{a}_{{i}} >\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\:\:\Rightarrow\mathrm{2}{b}_{{i}} =\mathrm{3}{b}_{{i}} =\mathrm{2}{a}_{{i}} \Rightarrow{a}_{{i}} ={b}_{{i}} =\mathrm{0} \\ $$$${A}\left({iii}\right):\:\mathrm{3}{a}_{{i}} >\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} <\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\:\:\Rightarrow\mathrm{2}{b}_{{i}} =\mathrm{2}{a}_{{i}} \Rightarrow{a}_{{i}} ={b}_{{i}} \\ $$$$ \\ $$$${B}\left({i}\right):\:\mathrm{3}{a}_{{i}} =\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} >\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\:\:\Rightarrow\mathrm{3}{a}_{{i}} =\mathrm{2}{b}_{{i}} =\mathrm{3}{b}_{{i}} \Rightarrow{a}_{{i}} ={b}_{{i}} =\mathrm{0} \\ $$$${B}\left({ii}\right):\:\mathrm{3}{a}_{{i}} =\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\:\Rightarrow\mathrm{3}{a}_{{i}} =\mathrm{2}{b}_{{i}} =\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} \Rightarrow{a}_{{i}} ={b}_{{i}} =\mathrm{0} \\ $$$${B}\left({iii}\right):\:\mathrm{3}{a}_{{i}} =\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} <\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\Rightarrow\mathrm{3}{a}_{{i}} =\mathrm{2}{b}_{{i}} =\mathrm{2}{a}_{{i}} \Rightarrow{a}_{{i}} ={b}_{{i}} =\mathrm{0} \\ $$$$ \\ $$$${C}\left({i}\right):\:\mathrm{3}{a}_{{i}} <\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} >\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\:\:\Rightarrow\mathrm{3}{a}_{{i}} =\mathrm{3}{b}_{{i}} \Rightarrow{a}_{{i}} ={b}_{{i}} \\ $$$${C}\left({ii}\right):\:\mathrm{3}{a}_{{i}} <\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\Rightarrow\mathrm{3}{a}_{{i}} =\mathrm{2}{a}_{{i}} =\mathrm{3}{b}_{{i}} \Rightarrow{a}_{{i}} ={b}_{{i}} \\ $$$${C}\left({iii}\right):\:\mathrm{3}{a}_{{i}} <\mathrm{2}{b}_{{i}} \:\wedge\:\mathrm{2}{a}_{{i}} <\mathrm{3}{b}_{{i}} \\ $$$$\:\:\:\:\:\:\mathrm{min}\left(\mathrm{3}{a}_{{i}} ,\:\mathrm{2}{b}_{{i}} \right)=\mathrm{min}\left(\mathrm{2}{a}_{{i}} ,\:\mathrm{3}{b}_{{i}} \right) \\ $$$$\:\:\:\:\:\Rightarrow\mathrm{3}{a}_{{i}} =\mathrm{2}{a}_{{i}} \Rightarrow{a}_{{i}} =\mathrm{0} \\ $$$$ \\ $$$${Possible}\:{conditions}\:{for}\:{exponents}\:{of} \\ $$$$\:{prime}\:{factors}\:{of}\:\mathrm{x}\:\&\:\mathrm{y} \\ $$$$\left({i}\right)\:{a}_{{i}} =\mathrm{0}\::\:\mathrm{x}\:\:\mathrm{contain}/{s}\:\:{factor}/{s}\:\:\:{p}_{{i}} ^{\mathrm{0}} \\ $$$$\:\:\:\:\:\:{while}\:\mathrm{y}\:{cotain}/{s}\:\:\:{p}_{{i}} ^{{m}} \:{where}\:{m}\in\mathbb{W}. \\ $$$$\:\:\:\:\:\:{For}\:{simple}\:{example}\:\mathrm{x}=\:{p}_{{i}} ^{\mathrm{0}} \:=\mathrm{1\&}\:\mathrm{y}={p}_{{i}} ^{{m}} \\ $$$$\:\:\:\:\mathrm{gcd}\left(\left(\mathrm{1}\right)^{\mathrm{3}} ,\left({p}_{{i}} ^{{m}} \right)^{\mathrm{2}} \right)=\mathrm{gcd}\left(\left(\mathrm{1}\right)^{\mathrm{2}} ,\left({p}_{{i}} ^{{m}} \right)^{\mathrm{3}} \right)=\mathrm{1} \\ $$$$\:\left({ii}\right)\:{b}_{{i}} =\mathrm{0}/{a}_{{i}} ={b}_{{i}} =\mathrm{0}\::\:{Similar}\:{explanation} \\ $$$$\:\:\left({iii}\right)\:{a}_{{i}} ={b}_{{i}} :\mathrm{x}\:\&\:\mathrm{y}\:{both}\:\mathrm{contain}\:\:{p}_{{i}} ^{{k}} \\ $$$$\:\:{Any}\:{combination}\:{of}\:{these}\:{conditions} \\ $$$${can}\:{be}\:{applied}.\:{For}\:{an}\:{example} \\ $$$${Solution}: \\ $$$$\mathrm{x}=\Pi{p}_{{i}} ^{\mathrm{0}} ×\Pi{p}_{{j}} ^{{m}_{{j}} } ×\Pi{p}_{{k}} ^{{n}_{{k}} } \\ $$$$\mathrm{y}=\Pi{p}_{{i}} ^{{l}_{{i}} } ×\Pi{p}_{{j}} ^{\mathrm{0}} ×\Pi{p}_{{k}} ^{{n}_{{k}} } \\ $$$$ \\ $$
Commented by Rasheed.Sindhi last updated on 21/Jun/19
Note:The answer is almost complete although it is not perfect. The answer suggest a general method how to compose x & y to meet the condition gcd(x^3 ,y^2 )=gcd(x^2 ,y^3 ) Rule1: If any prime factor in x (or y) has exponent 0, same prime in y(or in x) has any exponent from whole numbers. Rule2: If any prime has exponent other than 0 in x (or y),same prime in y(or x has same exponent. x=3^2 .7^0 .2^4 =144 y=3^2 .7^3 .2^0 =3087 ^• exponents equal ^• exponent 0 in a primefactor of x Any exponent in the same prime of y ^• exponent 0 in a primefactor of y Any exponent in the same prime of x
$${Note}:{The}\:{answer}\:{is}\:{almost}\:{complete} \\ $$$${although}\:{it}\:{is}\:{not}\:{perfect}. \\ $$$${The}\:{answer}\:{suggest}\:{a}\:\mathrm{general}\:{method}\:{how}\:{to} \\ $$$${compose}\:\mathrm{x}\:\&\:\mathrm{y}\:{to}\:{meet}\:{the}\:{condition} \\ $$$$\:\:\:\mathrm{gcd}\left(\mathrm{x}^{\mathrm{3}} ,\mathrm{y}^{\mathrm{2}} \right)=\mathrm{gcd}\left(\mathrm{x}^{\mathrm{2}} ,\mathrm{y}^{\mathrm{3}} \right) \\ $$$$ \\ $$$${Rule}\mathrm{1}:\:{If}\:{any}\:{prime}\:{factor}\:{in}\:{x}\:\left({or}\:{y}\right) \\ $$$${has}\:{exponent}\:\mathrm{0},\:{same}\:{prime}\:{in}\:{y}\left({or}\:{in}\:{x}\right) \\ $$$${has}\:{any}\:{exponent}\:{from}\:{whole}\:{numbers}. \\ $$$${Rule}\mathrm{2}:\:{If}\:{any}\:{prime}\:{has}\:{exponent}\:{other} \\ $$$${than}\:\mathrm{0}\:{in}\:{x}\:\left({or}\:{y}\right),{same}\:{prime}\:{in}\:{y}\left({or}\:{x}\right. \\ $$$${has}\:{same}\:{exponent}. \\ $$$$\mathrm{x}=\mathrm{3}^{\mathrm{2}} .\mathrm{7}^{\mathrm{0}} .\mathrm{2}^{\mathrm{4}} =\mathrm{144} \\ $$$$\mathrm{y}=\mathrm{3}^{\mathrm{2}} .\mathrm{7}^{\mathrm{3}} .\mathrm{2}^{\mathrm{0}} =\mathrm{3087} \\ $$$$ \\ $$$$\:^{\bullet} {exponents}\:{equal} \\ $$$$\:^{\bullet} {exponent}\:\mathrm{0}\:{in}\:{a}\:{primefactor}\:{of}\:\mathrm{x} \\ $$$$\:\:{Any}\:{exponent}\:{in}\:{the}\:\mathrm{same}\:{prime}\:{of}\:\mathrm{y} \\ $$$$\:^{\bullet} {exponent}\:\mathrm{0}\:{in}\:{a}\:{primefactor}\:{of}\:\mathrm{y} \\ $$$$\:\:{Any}\:{exponent}\:{in}\:{the}\:\mathrm{same}\:{prime}\:{of}\:\mathrm{x} \\ $$$$ \\ $$$$\: \\ $$
Commented by Rasheed.Sindhi last updated on 23/Jun/19
Worthless answer of worthless question!
$${Worthless}\:{answer}\:{of}\:{worthless}\:{question}! \\ $$

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