Question Number 62534 by peter frank last updated on 22/Jun/19
Answered by tanmay last updated on 22/Jun/19
$${bi}\:{metal}\:{changed}\:{to}\:{a}\:{shape}\:{concave}.. \\ $$$$\:\:{as}\:\:\:\smallsmile\:{and}\:{touch}\:{upper}\:.\:{point}\:{to}\:{activate} \\ $$$${A}\:…{so}\:{A}\:{is}\:{cooler} \\ $$$${and}\:{B}\:{is}\:{heater}…{i}\:{think}\:{so} \\ $$
Commented by peter frank last updated on 24/Jun/19
$${thank}\:{you} \\ $$