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Question-66036




Question Number 66036 by aliesam last updated on 08/Aug/19
Answered by mr W last updated on 08/Aug/19
=2(1+2+3+...+(n/2))  =2×(((1+(n/2))(n/2))/2)  =((n(n+2))/4)
$$=\mathrm{2}\left(\mathrm{1}+\mathrm{2}+\mathrm{3}+…+\frac{{n}}{\mathrm{2}}\right) \\ $$$$=\mathrm{2}×\frac{\left(\mathrm{1}+\frac{{n}}{\mathrm{2}}\right)\frac{{n}}{\mathrm{2}}}{\mathrm{2}} \\ $$$$=\frac{{n}\left({n}+\mathrm{2}\right)}{\mathrm{4}} \\ $$

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