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Question-63900




Question Number 63900 by Rio Michael last updated on 10/Jul/19
Commented by Rio Michael last updated on 10/Jul/19
Inthe Diagram above ABCD and CDEF are parrallelograms  which lie in thesame plane.  AB^→ =p , BC^→ =q  and CF^→ =r    by considering area show that  ∣p×(q+r)∣ = ∣p×q∣ + ∣p×r∣
$${Inthe}\:{Diagram}\:{above}\:{ABCD}\:{and}\:{CDEF}\:{are}\:{parrallelograms} \\ $$$${which}\:{lie}\:{in}\:{thesame}\:{plane}. \\ $$$${A}\overset{\rightarrow} {{B}}=\boldsymbol{{p}}\:,\:{B}\overset{\rightarrow} {{C}}=\boldsymbol{{q}}\:\:{and}\:{C}\overset{\rightarrow} {{F}}=\boldsymbol{{r}}\:\: \\ $$$${by}\:{considering}\:{area}\:{show}\:{that}\:\:\mid\boldsymbol{{p}}×\left(\boldsymbol{{q}}+\boldsymbol{{r}}\right)\mid\:=\:\mid\boldsymbol{{p}}×\boldsymbol{{q}}\mid\:+\:\mid\boldsymbol{{p}}×\boldsymbol{{r}}\mid \\ $$

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