Question Number 129502 by MathSh last updated on 16/Jan/21
$$\mathrm{2}^{{x}} ={a} \\ $$$$\mathrm{3}^{{x}} ={b}^{−\mathrm{1}} \\ $$$$\mathrm{54}^{{x}} =? \\ $$
Answered by bramlexs22 last updated on 16/Jan/21
$$\mathrm{54}^{\mathrm{x}} \:=\:\mathrm{27}^{\mathrm{x}} .\mathrm{2}^{\mathrm{x}} \:=\:\left(\mathrm{3}^{\mathrm{x}} \right)^{\mathrm{3}} .\mathrm{2}^{\mathrm{x}} =\frac{{a}}{{b}^{\mathrm{3}} } \\ $$