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Question-129892




Question Number 129892 by mohammad17 last updated on 20/Jan/21
Answered by Ar Brandon last updated on 20/Jan/21
GP with U(1)=((11x)/(12)) and r=(1/(12))  S_∞ =((((11)/(12))x)/(1−(1/(12))))=x
$$\mathrm{GP}\:\mathrm{with}\:\mathrm{U}\left(\mathrm{1}\right)=\frac{\mathrm{11x}}{\mathrm{12}}\:\mathrm{and}\:\mathrm{r}=\frac{\mathrm{1}}{\mathrm{12}} \\ $$$$\mathrm{S}_{\infty} =\frac{\frac{\mathrm{11}}{\mathrm{12}}\mathrm{x}}{\mathrm{1}−\frac{\mathrm{1}}{\mathrm{12}}}=\mathrm{x} \\ $$

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