Question Number 130119 by Study last updated on 22/Jan/21
$${li}\underset{{x}\rightarrow\mathrm{15}} {{m}log}\left({x}−\mathrm{15}\right)=??\:{or}\:{limit}\:{has}? \\ $$
Answered by Olaf last updated on 22/Jan/21
$$\underset{{x}\rightarrow\mathrm{15}^{−} } {\mathrm{lim}}\:\mathrm{ln}\left({x}−\mathrm{15}\right)\:\mathrm{is}\:\mathrm{undefined} \\ $$$$\mathrm{because}\:{x}−\mathrm{15}\:\mathrm{canno}'\mathrm{t}\:\mathrm{be}\:\mathrm{negative} \\ $$$$\underset{{x}\rightarrow\mathrm{15}^{+} } {\mathrm{lim}}\:\mathrm{ln}\left({x}−\mathrm{15}\right)\:=\:\underset{\mathrm{X}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\mathrm{lnX}\:=\:−\infty \\ $$