Question Number 64788 by Rio Michael last updated on 21/Jul/19
$${two}\:{consercutive}\:{integers}\:{between}\:{which}\:{a}\:{root}\:{of}\:{the}\:{equation}\:{lie}\:{are}: \\ $$$${x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{2}=\mathrm{0} \\ $$
Commented by MJS last updated on 21/Jul/19
$$\mathrm{the}\:\mathrm{roots}\:\mathrm{are}\:{x}=−\mathrm{2}\:\mathrm{and}\:{x}=−\mathrm{1}\:\mathrm{so}\:\mathrm{there}'\mathrm{s}\:\mathrm{no} \\ $$$$\mathrm{solution}\:\mathrm{to}\:\mathrm{your}\:\mathrm{question} \\ $$$$−\mathrm{3}<{x}<−\mathrm{1}\:\vee\:−\mathrm{2}<{x}<\mathrm{0} \\ $$$$\mathrm{if}\:\mathrm{we}\:\mathrm{take}\:\leqslant\:\mathrm{it}\:\mathrm{can}\:\mathrm{be}\:\mathrm{solved} \\ $$$$−\mathrm{2}\leqslant{x}\leqslant−\mathrm{1} \\ $$
Commented by Rio Michael last updated on 21/Jul/19
$${thanks}\:{sir} \\ $$