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3-x-x-1-dx-




Question Number 130678 by EDWIN88 last updated on 28/Jan/21
 ∫ ((3(√x))/(x−1)) dx ?
3xx1dx?
Answered by liberty last updated on 28/Jan/21
L = ∫ ((3(√x))/(x−1)) dx ; [ x=u^2  ]  L=6∫ (u^2 /(u^2 −1)) du = 6∫ (1+(1/(u^2 −1)))du  L=6u+6∫ (du/(u^2 −1)) =6(√x) +3∫( (1/(u−1))−(1/(u+1)))du   L=6(√x) +3ln ∣(((√x)−1)/( (√x)+1)) ∣ + c
L=3xx1dx;[x=u2]L=6u2u21du=6(1+1u21)duL=6u+6duu21=6x+3(1u11u+1)duL=6x+3lnx1x+1+c

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