Menu Close

Question-193280




Question Number 193280 by Mingma last updated on 09/Jun/23
Answered by AST last updated on 09/Jun/23
1000def^(____) +abc^(____) =6000abc^(____) +6def^(____) ⇒((def)/(abc))=((5999)/(994))=((857)/(142))  ⇒abcdef^(________) =142857
$$\mathrm{1000}\overset{\_\_\_\_} {{def}}+\overset{\_\_\_\_} {{abc}}=\mathrm{6000}\overset{\_\_\_\_} {{abc}}+\mathrm{6}\overset{\_\_\_\_} {{def}}\Rightarrow\frac{{def}}{{abc}}=\frac{\mathrm{5999}}{\mathrm{994}}=\frac{\mathrm{857}}{\mathrm{142}} \\ $$$$\Rightarrow\overset{\_\_\_\_\_\_\_\_} {{abcdef}}=\mathrm{142857} \\ $$
Commented by Mingma last updated on 09/Jun/23
Perfect ��

Leave a Reply

Your email address will not be published. Required fields are marked *