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If-every-element-of-a-third-order-determinant-of-value-is-multiplied-by-5-then-the-value-of-new-determinant-is-




Question Number 81872 by zainal tanjung last updated on 16/Feb/20
If every element of a third order  determinant of value △ is multiplied by  5, then the value of new determinant is
$$\mathrm{If}\:\mathrm{every}\:\mathrm{element}\:\mathrm{of}\:\mathrm{a}\:\mathrm{third}\:\mathrm{order} \\ $$$$\mathrm{determinant}\:\mathrm{of}\:\mathrm{value}\:\bigtriangleup\:\mathrm{is}\:\mathrm{multiplied}\:\mathrm{by} \\ $$$$\mathrm{5},\:\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{new}\:\mathrm{determinant}\:\mathrm{is} \\ $$
Answered by MJS last updated on 16/Feb/20
5^3 Δ=125Δ
$$\mathrm{5}^{\mathrm{3}} \Delta=\mathrm{125}\Delta \\ $$

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