Question Number 517 by Yugi last updated on 25/Jan/15
$${A}\:{person}\:{is}\:{said}\:{to}\:{be}\:{n}\:{years}\:{old}\:\left(\:{where}\:{n}\:{is}\:{a}\:{non}−{negative}\:{integer}\right)\:{if}\: \\ $$$${the}\:{person}\:{has}\:{lived}\:{at}\:{least}\:{n}\:{years}\:{and}\:{has}\:{not}\:{lived}\:{n}+\mathrm{1}\:{years}.\:{At}\:{some}\:{point} \\ $$$${Tom}\:{is}\:\mathrm{4}\:{years}\:{old}\:{and}\:{John}\:{is}\:{three}\:{times}\:{as}\:{old}\:{as}\:{Mary}.\:{At}\:{another}\:{time}, \\ $$$${Mary}\:{is}\:{twice}\:{as}\:{old}\:{as}\:{Tom}\:{and}\:{John}\:{is}\:{five}\:{times}\:{as}\:{old}\:{as}\:{Tom}.\:{At}\:{a}\:{third}\: \\ $$$${time},\:{John}\:{is}\:{twice}\:{as}\:{old}\:{as}\:{Mary}\:{and}\:{Tom}\:{is}\:{t}\:{years}\:{old}.\:{What}\:{is}\:{the}\:{largest} \\ $$$${possible}\:{value}\:{of}\:{t}? \\ $$
Commented by prakash jain last updated on 23/Jan/15
$${T},\:{J},\:{M}\:{are}\:{ages}\:{of}\:{Tom},\:{John}\:{and}\:{Mary} \\ $$$${p}_{\mathrm{1}} \\ $$$${T}_{\mathrm{1}} =\mathrm{4} \\ $$$${J}_{\mathrm{1}} =\mathrm{3}{M}_{\mathrm{1}} \\ $$$${p}_{\mathrm{2}} \:{Let}\:{us}\:{say}\:{k}\:{years}\:{from}\:{p}_{\mathrm{1}} \\ $$$${T}_{\mathrm{2}} =\mathrm{4}+{k} \\ $$$${M}_{\mathrm{2}} =\mathrm{2}{T}_{\mathrm{2}} =\mathrm{8}+\mathrm{2}{k} \\ $$$${J}_{\mathrm{2}} =\mathrm{5}{T}_{\mathrm{2}} =\mathrm{20}+\mathrm{5}{k} \\ $$$${M}_{\mathrm{1}} =\mathrm{8}+\mathrm{2}{k}−{k}=\mathrm{8}+{k} \\ $$$${J}_{\mathrm{1}} =\mathrm{20}+\mathrm{5}{k}−{k}=\mathrm{20}+\mathrm{4}{k} \\ $$$${M}_{\mathrm{1}} =\mathrm{8}+\mathrm{2}{k}−{k}=\mathrm{8}+{k} \\ $$$${J}_{\mathrm{1}} =\mathrm{3}{M}_{\mathrm{1}} \Rightarrow\mathrm{20}+\mathrm{4}{k}=\mathrm{24}+\mathrm{3}{k}\Rightarrow{k}=\mathrm{4} \\ $$$${M}_{\mathrm{1}} =\mathrm{12},\:{J}_{\mathrm{1}} =\mathrm{36},\:{M}_{\mathrm{2}} =\mathrm{16},\:{J}_{\mathrm{2}} =\mathrm{40},\:{T}_{\mathrm{2}} =\mathrm{8} \\ $$$${p}_{\mathrm{3}} \:{Let}\:{us}\:{say}\:{l}\:{years}\:{from}\:{p}_{\mathrm{1}} \\ $$$${T}_{\mathrm{3}} ={t}=\mathrm{4}+{l} \\ $$$${J}_{\mathrm{3}} =\mathrm{2}{M}_{\mathrm{3}} \\ $$$${J}_{\mathrm{3}} ={J}_{\mathrm{1}} +{l}=\mathrm{36}+{l} \\ $$$${M}_{\mathrm{3}} ={M}_{\mathrm{1}} +{l}=\mathrm{12}+{l} \\ $$$$\mathrm{36}+{l}=\mathrm{2}\left(\mathrm{12}+{l}\right) \\ $$$$\mathrm{36}+{l}=\mathrm{24}+\mathrm{2}{l}\Rightarrow{l}=\mathrm{12} \\ $$$${So}\:{t}=\mathrm{4}+\mathrm{12}=\mathrm{16} \\ $$
Answered by prakash jain last updated on 23/Jan/15
$${See}\:{comment}\:{only}\:{one}\:{solution}\:{t}=\mathrm{16} \\ $$
Commented by prakash jain last updated on 23/Jan/15
$${T}_{\mathrm{3}} ={t}=\mathrm{16} \\ $$$${M}_{\mathrm{3}} =\mathrm{24} \\ $$$${J}_{\mathrm{3}} =\mathrm{48} \\ $$