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If-a-b-c-d-are-in-GP-then-a-3-b-3-1-b-3-c-3-1-c-3-a-3-1-are-in-




Question Number 31953 by 24444355 last updated on 17/Mar/18
If a, b, c, d are in GP, then (a^3 +b^3 )^(−1) ,   (b^3 +c^3 )^(−1) , (c^3 +a^3 )^(−1)  are in
$$\mathrm{If}\:{a},\:{b},\:{c},\:{d}\:\mathrm{are}\:\mathrm{in}\:\mathrm{GP},\:\mathrm{then}\:\left({a}^{\mathrm{3}} +{b}^{\mathrm{3}} \right)^{−\mathrm{1}} ,\: \\ $$$$\left({b}^{\mathrm{3}} +{c}^{\mathrm{3}} \right)^{−\mathrm{1}} ,\:\left({c}^{\mathrm{3}} +{a}^{\mathrm{3}} \right)^{−\mathrm{1}} \:\mathrm{are}\:\mathrm{in} \\ $$
Commented by Rasheed.Sindhi last updated on 18/Mar/18
Why is d disappeared in “after then” part?
$$\mathrm{Why}\:\mathrm{is}\:{d}\:\mathrm{disappeared}\:\mathrm{in}\:“\mathrm{after}\:\mathrm{then}''\:\mathrm{part}? \\ $$
Commented by rahul 19 last updated on 18/Mar/18
i think there should not be any d .
$${i}\:{think}\:{there}\:{should}\:{not}\:{be}\:{any}\:{d}\:. \\ $$

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