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Question-193761




Question Number 193761 by AZEEZAY last updated on 19/Jun/23
Answered by Frix last updated on 19/Jun/23
Simply use this:  c=log_b  a ⇔ a=b^c
$$\mathrm{Simply}\:\mathrm{use}\:\mathrm{this}: \\ $$$${c}=\mathrm{log}_{{b}} \:{a}\:\Leftrightarrow\:{a}={b}^{{c}} \\ $$
Answered by SaRahAli last updated on 19/Jun/23
T=0.1585
$$\mathrm{T}=\mathrm{0}.\mathrm{1585} \\ $$

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