Menu Close

Question-195248




Question Number 195248 by arkanshh last updated on 28/Jul/23
Commented by Frix last updated on 28/Jul/23
Approximate  x_1 ≈−.811328  x_2 ≈4.53236
$$\mathrm{Approximate} \\ $$$${x}_{\mathrm{1}} \approx−.\mathrm{811328} \\ $$$${x}_{\mathrm{2}} \approx\mathrm{4}.\mathrm{53236} \\ $$
Commented by arkanshh last updated on 29/Jul/23
actually the exact solution is i.  I wish if someone knows the method of solution
$${actually}\:{the}\:{exact}\:{solution}\:{is}\:{i}. \\ $$$${I}\:{wish}\:{if}\:{someone}\:{knows}\:{the}\:{method}\:{of}\:{solution} \\ $$
Commented by Frix last updated on 29/Jul/23
I don′t think there′s an exact method.  I didn′t think of x∉R but yes, obviously  x=±i is a solution.
$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{there}'\mathrm{s}\:\mathrm{an}\:\mathrm{exact}\:\mathrm{method}. \\ $$$$\mathrm{I}\:\mathrm{didn}'\mathrm{t}\:\mathrm{think}\:\mathrm{of}\:{x}\notin\mathbb{R}\:\mathrm{but}\:\mathrm{yes},\:\mathrm{obviously} \\ $$$${x}=\pm\mathrm{i}\:\mathrm{is}\:\mathrm{a}\:\mathrm{solution}. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *