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During-an-invasion-In-the-amazon-dominion-Every-evening-every-invader-kills-an-amazon-warrior-Every-morning-every-amazon-kills-an-invader-soldier-The-8-th-day-evening-there-remains-o




Question Number 196070 by sniper237 last updated on 17/Aug/23
During an invasion   In the amazon dominion  Every evening , every  invader   kills  an  amazon warrior   Every morning , every amazon  kills   an invader soldier  The 8^(th)  day evening , there remains   only one amazon  and no invader    How many  were they in each part ?
$${During}\:{an}\:{invasion}\: \\ $$$${In}\:{the}\:{amazon}\:{dominion} \\ $$$${Every}\:{evening}\:,\:{every}\:\:{invader}\: \\ $$$${kills}\:\:{an}\:\:{amazon}\:{warrior}\: \\ $$$${Every}\:{morning}\:,\:{every}\:{amazon} \\ $$$${kills}\:\:\:{an}\:{invader}\:{soldier} \\ $$$${The}\:\mathrm{8}^{{th}} \:{day}\:{evening}\:,\:{there}\:{remains}\: \\ $$$${only}\:{one}\:{amazon}\:\:{and}\:{no}\:{invader} \\ $$$$ \\ $$$${How}\:{many}\:\:{were}\:{they}\:{in}\:{each}\:{part}\:? \\ $$
Answered by jabarsing last updated on 18/Aug/23
1597 amazon  987 invader
$$\mathrm{1597}\:{amazon} \\ $$$$\mathrm{987}\:{invader}\: \\ $$
Commented by sniper237 last updated on 18/Aug/23
That′s right    { ((x_(n+1)  = x_n −y_n )),((y_(n+1) = y_n −x_(n+1) )) :}and  x_8 =1 , y_8 =0  V_(n+1)  = AV_n      ⇒ V_8  = A^8 V_0     ((x_0 ),(y_0 ) )= (((1     −1)),((−1     2)) )^(−8)  ((x_8 ),(y_8 ) )
$${That}'{s}\:{right}\: \\ $$$$\begin{cases}{{x}_{{n}+\mathrm{1}} \:=\:{x}_{{n}} −{y}_{{n}} }\\{{y}_{{n}+\mathrm{1}} =\:{y}_{{n}} −{x}_{{n}+\mathrm{1}} }\end{cases}{and}\:\:{x}_{\mathrm{8}} =\mathrm{1}\:,\:{y}_{\mathrm{8}} =\mathrm{0} \\ $$$${V}_{{n}+\mathrm{1}} \:=\:{AV}_{{n}} \:\:\:\:\:\Rightarrow\:{V}_{\mathrm{8}} \:=\:{A}^{\mathrm{8}} {V}_{\mathrm{0}} \: \\ $$$$\begin{pmatrix}{{x}_{\mathrm{0}} }\\{{y}_{\mathrm{0}} }\end{pmatrix}=\begin{pmatrix}{\mathrm{1}\:\:\:\:\:−\mathrm{1}}\\{−\mathrm{1}\:\:\:\:\:\mathrm{2}}\end{pmatrix}^{−\mathrm{8}} \begin{pmatrix}{{x}_{\mathrm{8}} }\\{{y}_{\mathrm{8}} }\end{pmatrix}\: \\ $$

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