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Question-196115




Question Number 196115 by sonukgindia last updated on 18/Aug/23
Answered by Rasheed.Sindhi last updated on 18/Aug/23
xy+66x−88y−88×66=23333−88×66  x(y+66)−88(y+66)=17525  (x−88)(y+66)=5^2 ×701    { ((x−88=1_(x=89 )  ∧ y+66=23333_(y=23267) )),((x−88=5 ∧ y+66=3505_(x=93 , y=3439) )),((x−88=25 ∧ y+66=701)),((x−88=701 ∧ y+66=25)),((x−88=3505 ∧ y+66=5)),((x−88=23333 ∧ y+66=1)) :}
$${xy}+\mathrm{66}{x}−\mathrm{88}{y}−\mathrm{88}×\mathrm{66}=\mathrm{23333}−\mathrm{88}×\mathrm{66} \\ $$$${x}\left({y}+\mathrm{66}\right)−\mathrm{88}\left({y}+\mathrm{66}\right)=\mathrm{17525} \\ $$$$\left({x}−\mathrm{88}\right)\left({y}+\mathrm{66}\right)=\mathrm{5}^{\mathrm{2}} ×\mathrm{701}\: \\ $$$$\begin{cases}{\underset{{x}=\mathrm{89}\:} {{x}−\mathrm{88}=\mathrm{1}}\:\wedge\:\underset{{y}=\mathrm{23267}} {{y}+\mathrm{66}=\mathrm{23333}}}\\{\underset{{x}=\mathrm{93}\:,\:{y}=\mathrm{3439}} {{x}−\mathrm{88}=\mathrm{5}\:\wedge\:{y}+\mathrm{66}=\mathrm{3505}}}\\{{x}−\mathrm{88}=\mathrm{25}\:\wedge\:{y}+\mathrm{66}=\mathrm{701}}\\{{x}−\mathrm{88}=\mathrm{701}\:\wedge\:{y}+\mathrm{66}=\mathrm{25}}\\{{x}−\mathrm{88}=\mathrm{3505}\:\wedge\:{y}+\mathrm{66}=\mathrm{5}}\\{{x}−\mathrm{88}=\mathrm{23333}\:\wedge\:{y}+\mathrm{66}=\mathrm{1}}\end{cases} \\ $$

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