Question Number 196364 by mathlove last updated on 23/Aug/23
$${xp}\left({x}\right)={x}^{\mathrm{3}} −\mathrm{2}{x}^{\mathrm{2}} +{x}−{a} \\ $$$${p}\left(−\mathrm{1}\right)=? \\ $$
Answered by MM42 last updated on 23/Aug/23
$${x}=\mathrm{0}\Rightarrow{a}=\mathrm{0} \\ $$$${x}=−\mathrm{1}\Rightarrow{p}\left(−\mathrm{1}\right)=\mathrm{4} \\ $$