Question Number 197104 by MrGHK last updated on 07/Sep/23
Commented by TheHoneyCat last updated on 08/Sep/23
$$\mathrm{Are}\:\mathrm{you}\:\mathrm{looking}\:\mathrm{for}\:\mathrm{a}\:\mathrm{functional}\:\mathrm{answere}? \\ $$$$\mathrm{because}\:\mathrm{if}\:\mathrm{you}\:\mathrm{are}\:\mathrm{expecting}\:\mathrm{a}\:\mathrm{solution}: \\ $$$${x}\left({t}\right)=… \\ $$$$\mathrm{then}\:\mathrm{there}\:\mathrm{is}\:\mathrm{an}\:\mathrm{issue}:\:{y}\:\mathrm{is}\:\mathrm{not}\:\mathrm{defined}! \\ $$
Commented by MrGHK last updated on 08/Sep/23
$${yes}\:{functional}\:{answer} \\ $$
Commented by TheHoneyCat last updated on 08/Sep/23
$$\mathrm{I}'\mathrm{ve}\:\mathrm{reached}\:\mathrm{the}\:\mathrm{point}\:\mathrm{where} \\ $$$${Y}=\frac{\mathrm{3}+\mathrm{5}{i}\omega}{\mathrm{2}\omega^{\mathrm{2}} }{X}−\frac{{i}\pi}{\omega^{\mathrm{2}} }\theta\left({w}\right) \\ $$$$ \\ $$$$\mathrm{with}\:\mathrm{conditions} \\ $$$$\frac{\mathrm{d}^{\mathrm{2}} {y}}{\mathrm{d}{t}^{\mathrm{2}} }\left({t}=\mathrm{0}\right)=−\mathrm{1} \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{realy}\:\mathrm{know}\:\mathrm{how}\:\mathrm{one}\:\mathrm{would}\:\mathrm{go} \\ $$$$\mathrm{further}. \\ $$$$\mathrm{nor},\:\mathrm{in}\:\mathrm{fact},\:\mathrm{if}\:\mathrm{one}\:\mathrm{can}… \\ $$