Question Number 137746 by AzizMuzeifa last updated on 06/Apr/21
Answered by bemath last updated on 06/Apr/21
$$\mathrm{1}.{x}^{\mathrm{2}} +\mathrm{1}.{x}\:=\:\mathrm{1}.\mathrm{4}^{\mathrm{3}} +\mathrm{0}+\mathrm{2}.\mathrm{4}+\mathrm{0} \\ $$$${x}^{\mathrm{2}} +{x}−\mathrm{72}=\mathrm{0} \\ $$$$\left({x}+\mathrm{9}\right)\left({x}−\mathrm{8}\right)=\mathrm{0} \\ $$$${x}=\mathrm{8}\:{solution} \\ $$$${x}=−\mathrm{9}\:{no}\:{solution} \\ $$