Question Number 197644 by gungun last updated on 25/Sep/23
Commented by gungun last updated on 25/Sep/23
$${find}\:{the}\:{pink}\:{area} \\ $$
Answered by Rasheed.Sindhi last updated on 25/Sep/23
$${Pink}\:{area}\:{in}\:{terms}\:{of}\:{R}\:\&\:{r}: \\ $$$${A}_{{p}} =\pi\left({R}^{\mathrm{2}} −{r}^{\mathrm{2}} \right) \\ $$$${On}\:{the}\:{other}\:{hand} \\ $$$${x}^{\mathrm{2}} +{r}^{\mathrm{2}} ={R}^{\mathrm{2}} \\ $$$${or}\:\:\:{R}^{\mathrm{2}} −{r}^{\mathrm{2}} ={x}^{\mathrm{2}} \\ $$$${Therefore} \\ $$$${A}_{{p}} =\pi{x}^{\mathrm{2}} \\ $$