Menu Close

e-2-2-xdx-




Question Number 6700 by jose14918645@gmail.com last updated on 14/Jul/16
∫(e^(−2+2) xdx
$$\int\left({e}^{−\mathrm{2}+\mathrm{2}} {xdx}\right. \\ $$
Answered by FilupSmith last updated on 15/Jul/16
=∫e^0 xdx  =∫xdx  =(1/2)x^2 +c
$$=\int{e}^{\mathrm{0}} {xdx} \\ $$$$=\int{xdx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} +{c} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *