Question Number 6700 by jose14918645@gmail.com last updated on 14/Jul/16
$$\int\left({e}^{−\mathrm{2}+\mathrm{2}} {xdx}\right. \\ $$
Answered by FilupSmith last updated on 15/Jul/16
$$=\int{e}^{\mathrm{0}} {xdx} \\ $$$$=\int{xdx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} +{c} \\ $$