3-8-3h-p-2-3ph-3h-2-1-and-3h-p-3-16-p-3h-2-1-h-3-h-c-Find-p-and-h-in-terms-of-0-lt-c-lt-2-3-3-

Tinku Tara October 19, 2023 Algebra 0 Comments

Question Number 198414 by ajfour last updated on 19/Oct/23

(3/8)(3h−p)^2 +3ph=(3h^2 −1) and (((3h−p)^3 )/(16))+p(3h^2 −1)=h^3 −h−c Find p and h in terms of 0<c<(2/(3(√3)))∙

$$\frac{\mathrm{3}}{\mathrm{8}}\left(\mathrm{3}{h}−{p}\right)^{\mathrm{2}} +\mathrm{3}{ph}=\left(\mathrm{3}{h}^{\mathrm{2}} −\mathrm{1}\right) \\ $$$${and} \\ $$$$\frac{\left(\mathrm{3}{h}−{p}\right)^{\mathrm{3}} }{\mathrm{16}}+{p}\left(\mathrm{3}{h}^{\mathrm{2}} −\mathrm{1}\right)={h}^{\mathrm{3}} −{h}−{c} \\ $$$${Find}\:\:{p}\:{and}\:{h}\:\:{in}\:{terms}\:{of}\:\mathrm{0}<{c}<\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}\centerdot \\ $$

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3-8-3h-p-2-3ph-3h-2-1-and-3h-p-3-16-p-3h-2-1-h-3-h-c-Find-p-and-h-in-terms-of-0-lt-c-lt-2-3-3-

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