Question Number 198565 by tri26112004 last updated on 22/Oct/23
$${Let}\:{a},{b},{c}\:\in\:{R}^{+} \:{such}\:{that}\:{a}+{b}+{c}=\mathrm{1}. \\ $$$$\:{Prove}\:{that}:\:\:\:\:{b}+{c}\geqslant\mathrm{16}{abc} \\ $$
Let-a-b-c-R-such-that-a-b-c-1-Prove-that-b-c-16abc-