Question Number 6733 by Tawakalitu. last updated on 17/Jul/16
Answered by sandy_suhendra last updated on 18/Jul/16
$${t}_{\mathrm{0}} \:=\:\mathrm{0}^{{o}} {C}\:\left({temperature}\:{of}\:{ice}\right) \\ $$$${t}_{\mathrm{1}} \:=\:\mathrm{100}^{{o}} {C}\:\left({temperature}\:{of}\:{stram}\right) \\ $$$${t}_{\mathrm{2}} \:=\:\mathrm{75}^{{o}} {C} \\ $$$${h}_{\mathrm{1}} −{h}_{\mathrm{0}} =\mathrm{300}\:{mm} \\ $$$${h}_{\mathrm{2}} =? \\ $$$$\frac{{t}_{\mathrm{1}} −{t}_{{o}} }{{t}_{\mathrm{2}} −{t}_{{o}} }\:=\:\frac{{h}_{\mathrm{1}} −{h}_{\mathrm{0}} }{{h}_{\mathrm{2}} −{h}_{\mathrm{0}} } \\ $$$$\frac{\mathrm{100}−\mathrm{0}}{\mathrm{75}−\mathrm{0}}\:=\:\frac{\mathrm{300}}{{h}_{\mathrm{2}} −{h}_{\mathrm{0}} } \\ $$$${h}_{\mathrm{2}} −{h}_{\mathrm{0}} \:=\:\mathrm{225}\:{mm} \\ $$
Commented by Tawakalitu. last updated on 18/Jul/16
$${Thanks}\bar {\:} \\ $$