Question Number 199480 by Abdullahrussell last updated on 04/Nov/23
Commented by mr W last updated on 04/Nov/23
$$=\frac{\mathrm{sin}\:\theta+\mathrm{sin}\:\mathrm{50}°+\mathrm{1}+\mathrm{sin}\:\mathrm{50}°}{\mathrm{cos}\:\theta+\mathrm{cos}\:\mathrm{50}°+\mathrm{0}−\mathrm{cos}\:\mathrm{50}°} \\ $$$$=\frac{\mathrm{sin}\:\theta+\mathrm{1}+\mathrm{2}\:\mathrm{sin}\:\mathrm{50}°}{\mathrm{cos}\:\theta} \\ $$