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find-x-in-the-interval-0-lt-x-lt-360-if-f-x-6sinx-is-12-




Question Number 202143 by otchereabdullai@gmail.com last updated on 21/Dec/23
 find x in the interval  0°<x<360° if    f(x)= 6sinx is −12
$$\:{find}\:{x}\:{in}\:{the}\:{interval}\:\:\mathrm{0}°<{x}<\mathrm{360}°\:{if} \\ $$$$\:\:{f}\left({x}\right)=\:\mathrm{6}{sinx}\:{is}\:−\mathrm{12} \\ $$
Commented by otchereabdullai@gmail.com last updated on 22/Dec/23
answer in the book is 210° and 330°   but i dont know how  he come about   it
$${answer}\:{in}\:{the}\:{book}\:{is}\:\mathrm{210}°\:{and}\:\mathrm{330}°\: \\ $$$${but}\:{i}\:{dont}\:{know}\:{how}\:\:{he}\:{come}\:{about}\: \\ $$$${it} \\ $$
Commented by AST last updated on 21/Dec/23
−6≤6sin(x)≤6
$$−\mathrm{6}\leqslant\mathrm{6}{sin}\left({x}\right)\leqslant\mathrm{6} \\ $$
Commented by otchereabdullai@gmail.com last updated on 22/Dec/23
answer should be interms of angles  sir
$${answer}\:{should}\:{be}\:{interms}\:{of}\:{angles} \\ $$$${sir} \\ $$
Commented by AST last updated on 22/Dec/23
6sin(x)≠−12 for any x
$$\mathrm{6}{sin}\left({x}\right)\neq−\mathrm{12}\:{for}\:{any}\:{x} \\ $$
Commented by AST last updated on 22/Dec/23
That′s −3 not −12
$${That}'{s}\:−\mathrm{3}\:{not}\:−\mathrm{12} \\ $$

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