Question Number 204038 by hardmath last updated on 04/Feb/24
$$\mathrm{y}\:=\:\left(\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{1}\right)\:\centerdot\:\mathrm{3}^{\boldsymbol{\mathrm{x}}} \\ $$$$\Rightarrow\:\mathrm{y}^{'} \:=\:? \\ $$
Answered by AST last updated on 04/Feb/24
$${y}^{'} =\mathrm{3}^{{x}+\mathrm{1}} \left({x}^{\mathrm{2}} \right)+\left({x}^{\mathrm{3}} +\mathrm{1}\right)\mathrm{3}^{{x}} {In}\left(\mathrm{3}\right) \\ $$