Question Number 204072 by Red1ight last updated on 05/Feb/24
$$\frac{\mathrm{sin}^{\mathrm{2}} \:\theta}{\mathrm{2}}=\mathrm{sin}\:\mathrm{2}\theta?\:\left(\mathrm{90}°>\theta>\mathrm{0}°\right) \\ $$
Answered by AST last updated on 05/Feb/24
$${sin}^{\mathrm{2}} \theta=\mathrm{4}{sin}\theta{cos}\theta\Rightarrow{tan}\theta=\mathrm{4}\Rightarrow\theta={tan}^{−\mathrm{1}} \left(\mathrm{4}\right)\approx\mathrm{75}.\mathrm{96}° \\ $$