Question Number 204236 by Panav last updated on 09/Feb/24
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Commented by Panav last updated on 09/Feb/24
Answered by JDamian last updated on 10/Feb/24
$${R}=\mathrm{14}\:\mathrm{cm} \\ $$$$\mathrm{2}×{S}_{{triangle}} =\:{R}^{\mathrm{2}} \mathrm{cos}^{\mathrm{2}} \:\mathrm{45}°\:=\:\frac{{R}^{\mathrm{2}} }{\mathrm{2}}\:=\:\mathrm{98}\:\:\:\mathrm{cm}^{\mathrm{2}} \\ $$$${S}_{{full}\:{circle}} =\:\:\pi{R}^{\mathrm{2}} \:\:=\:\:\mathrm{196}\pi\:\:\:\:\mathrm{cm}^{\mathrm{2}} \\ $$$$ \\ $$$${S}\:=\:\mathrm{196}\pi−\mathrm{98}\:\:\:\mathrm{cm}^{\mathrm{2}} \\ $$$$\mathrm{196}\pi−\mathrm{98}\:\:\:\notin\:\mathbb{N} \\ $$