Question Number 204330 by universe last updated on 13/Feb/24
Answered by AST last updated on 13/Feb/24
$$\mathrm{3}{a}+\mathrm{2}{b}+\mathrm{15}=\mathrm{0}\:\:\:\:\wedge\:\:\:\mathrm{6}{a}+\mathrm{2}{b}\leqslant\mathrm{0}\Rightarrow{b}\leqslant−\mathrm{3}{a} \\ $$$$\Rightarrow{b}=\frac{−\mathrm{15}−\mathrm{3}{a}}{\mathrm{2}}\leqslant−\mathrm{3}{a}\Rightarrow−\mathrm{15}−\mathrm{3}{a}\leqslant−\mathrm{6}{a}\Rightarrow\mathrm{3}{a}\leqslant\mathrm{15} \\ $$$$\Rightarrow{a}\leqslant\mathrm{5}\Rightarrow{max}\left({a}\mid{a}\in\mathbb{Z}\right)=\mathrm{5} \\ $$
Commented by universe last updated on 13/Feb/24
$${thank}\:{you}\:{sir} \\ $$