Question Number 204663 by LuisTony last updated on 24/Feb/24
Answered by TonyCWX08 last updated on 25/Feb/24
$$\mathrm{sin}\left(\mathrm{52}°\mathrm{20}'\right)=\frac{{h}}{\mathrm{1200}} \\ $$$${h}=\mathrm{1200sin}\left(\mathrm{52}°\mathrm{20}'\right) \\ $$$${h}\approx\mathrm{949}.\mathrm{9}{m} \\ $$