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Question-205117




Question Number 205117 by BaliramKumar last updated on 09/Mar/24
Answered by Rasheed.Sindhi last updated on 09/Mar/24
(x/y)+(y/x)=2  ⇒x^2 +y^2 =2xy  ⇒x^2 −2xy+y^2 =0  ⇒(x−y)^2 =0  ⇒x−y=0  ⇒x=y  ⇏ x≠y  (a) Zero
$$\frac{{x}}{{y}}+\frac{{y}}{{x}}=\mathrm{2} \\ $$$$\Rightarrow{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{2}{xy} \\ $$$$\Rightarrow{x}^{\mathrm{2}} −\mathrm{2}{xy}+{y}^{\mathrm{2}} =\mathrm{0} \\ $$$$\Rightarrow\left({x}−{y}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$$\Rightarrow{x}−{y}=\mathrm{0} \\ $$$$\Rightarrow{x}={y} \\ $$$$\nRightarrow\:{x}\neq{y} \\ $$$$\left({a}\right)\:{Zero} \\ $$
Commented by BaliramKumar last updated on 09/Mar/24
thanks
$$\mathrm{thanks} \\ $$

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