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Question-205306




Question Number 205306 by peter frank last updated on 15/Mar/24
Answered by A5T last updated on 15/Mar/24
2(3x^2 +4xy)=450⇒3x^2 +4xy=225  ⇒y=((225−3x^2 )/(4x))⇒v=3x^2 y=((3x(225−3x^2 ))/4)  =((675x−9x^2 )/4)
$$\mathrm{2}\left(\mathrm{3}{x}^{\mathrm{2}} +\mathrm{4}{xy}\right)=\mathrm{450}\Rightarrow\mathrm{3}{x}^{\mathrm{2}} +\mathrm{4}{xy}=\mathrm{225} \\ $$$$\Rightarrow{y}=\frac{\mathrm{225}−\mathrm{3}{x}^{\mathrm{2}} }{\mathrm{4}{x}}\Rightarrow{v}=\mathrm{3}{x}^{\mathrm{2}} {y}=\frac{\mathrm{3}{x}\left(\mathrm{225}−\mathrm{3}{x}^{\mathrm{2}} \right)}{\mathrm{4}} \\ $$$$=\frac{\mathrm{675}{x}−\mathrm{9}{x}^{\mathrm{2}} }{\mathrm{4}} \\ $$
Commented by peter frank last updated on 17/Mar/24
thank you
Commented by peter frank last updated on 17/Mar/24
help to solve Qn 2

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