Question Number 205817 by hardmath last updated on 31/Mar/24
$$\mathrm{2}^{\:\boldsymbol{\mathrm{x}}\:+\:\boldsymbol{\mathrm{log}}_{\mathrm{2}} \:\mathrm{3}} \:=\:\mathrm{12}\:\:\Rightarrow\:\:\mathrm{find}:\:\:\mathrm{x}\:=\:? \\ $$
Answered by A5T last updated on 31/Mar/24
$$\left(\mathrm{2}^{{x}} \right)\left(\mathrm{2}^{{log}_{\mathrm{2}} \mathrm{3}} \right)=\mathrm{12}\Rightarrow\left(\mathrm{2}^{{x}} \right)\left(\mathrm{3}\right)=\mathrm{12}\Rightarrow\mathrm{2}^{{x}} =\mathrm{4}\Rightarrow{x}=\mathrm{2} \\ $$
Answered by MM42 last updated on 31/Mar/24
$$\mathrm{2}^{{x}} ×\mathrm{3}=\mathrm{12}\Rightarrow{x}=\mathrm{2}\:\checkmark \\ $$