Question Number 207327 by hardmath last updated on 11/May/24
$$\left(\mathrm{x}−\mathrm{3}\right)\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{x}−\mathrm{2}}\:\:=\:\:\mathrm{0} \\ $$$$\mathrm{Find}:\:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$
Commented by A5T last updated on 11/May/24
$${x}=\mathrm{3}\:{or}\:\mathrm{2}\:{or}\:−\mathrm{1} \\ $$
Answered by Frix last updated on 11/May/24
$${pq}=\mathrm{0}\:\Rightarrow\:{p}=\mathrm{0}\vee{q}=\mathrm{0} \\ $$$$\sqrt{{r}}=\mathrm{0}\:\Leftrightarrow\:{r}=\mathrm{0} \\ $$$${p}={x}−\mathrm{3}=\mathrm{0} \\ $$$${q}=\sqrt{{x}^{\mathrm{2}} −{x}−\mathrm{2}}=\mathrm{0};\:{r}={x}^{\mathrm{2}} −{x}−\mathrm{2}=\mathrm{0} \\ $$$$\mathrm{Both}\:\mathrm{are}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{solve}. \\ $$