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Find-2-5-5-2-1-5-5-3-1-2-1-3-2-sin-7pi-4-




Question Number 207385 by hardmath last updated on 13/May/24
Find:  (√((2,5−(√5))^2 )) − (((1,5−(√5))^3 )^(1/2) ))^(1/3)  − (√2) sin ((7π)/4)
$$\mathrm{Find}: \\ $$$$\sqrt{\left(\mathrm{2},\mathrm{5}−\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }\:−\:\sqrt[{\mathrm{3}}]{\left.\left(\mathrm{1},\mathrm{5}−\sqrt{\mathrm{5}}\right)^{\mathrm{3}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} }\:−\:\sqrt{\mathrm{2}}\:\mathrm{sin}\:\frac{\mathrm{7}\pi}{\mathrm{4}} \\ $$
Commented by Frix last updated on 13/May/24
=(7/2)−(√5)−((√(6(−3+2(√5))))/4)−((√(2(−3+2(√5)))/4)i  ≈.520930688−.428972021i
$$=\frac{\mathrm{7}}{\mathrm{2}}−\sqrt{\mathrm{5}}−\frac{\sqrt{\mathrm{6}\left(−\mathrm{3}+\mathrm{2}\sqrt{\mathrm{5}}\right)}}{\mathrm{4}}−\frac{\sqrt{\mathrm{2}\left(−\mathrm{3}+\mathrm{2}\sqrt{\mathrm{5}}\right.}}{\mathrm{4}}\mathrm{i} \\ $$$$\approx.\mathrm{520930688}−.\mathrm{428972021i} \\ $$

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