Question Number 207466 by mr W last updated on 16/May/24
Answered by A5T last updated on 16/May/24
Commented by A5T last updated on 16/May/24
$$\mathrm{5}+?+\mathrm{1}+?−\left(\mathrm{3}+?−\mathrm{1}+\mathrm{4}\right)=?=\mathrm{2}{sh} \\ $$$$\left(\mathrm{5}_{{h}} \right)−\left(?−\mathrm{1}\right)_{{h}} =\mathrm{2}{h} \\ $$$$\frac{{s}}{\mathrm{2}}\left(\mathrm{5}_{{h}} −\left(?−\mathrm{1}\right)_{{h}} \right)=\mathrm{5}−\left(?−\mathrm{1}\right)=\mathrm{6}−?={sh} \\ $$$$\Rightarrow\mathrm{12}−\mathrm{2}?=?\Rightarrow?=\mathrm{4} \\ $$
Commented by mr W last updated on 16/May/24
��
Answered by mr W last updated on 16/May/24
Commented by mr W last updated on 16/May/24
$${A}+\mathrm{4}={B}+\mathrm{5}={C}+\mathrm{3}=\frac{{hexagon}}{\mathrm{3}} \\ $$$$\Rightarrow{B}={A}−\mathrm{1} \\ $$$$\Rightarrow{C}={A}+\mathrm{1} \\ $$$$\mathrm{4}×\left({A}−\mathrm{4}\right)=\left(\mathrm{3}+{A}+\mathrm{5}\right)−\left({B}+\mathrm{4}+{C}\right) \\ $$$$\mathrm{4}{A}−\mathrm{16}=\mathrm{4}−{A} \\ $$$$\Rightarrow{A}=\mathrm{4} \\ $$