Let-a-1-1-a-2-2-1-a-3-3-2-1-a-4-4-3-2-1-find-the-last-two-digits-of-a-23-and-so-on-

Tinku Tara August 5, 2024 Algebra 0 Comments

Question Number 210311 by Spillover last updated on 05/Aug/24

Let a_1 =1 a_2 =2^1 a_3 =3^((2^1 )) a_4 =4^((3^((2^1 )) )) find the last two digits of a_(23) and so on

$${Let}\:{a}_{\mathrm{1}} =\mathrm{1}\:\:\:{a}_{\mathrm{2}} =\mathrm{2}^{\mathrm{1}} \:\:\:\:{a}_{\mathrm{3}} =\mathrm{3}^{\left(\mathrm{2}^{\mathrm{1}} \right)} \:\:{a}_{\mathrm{4}} =\mathrm{4}^{\left(\mathrm{3}^{\left(\mathrm{2}^{\mathrm{1}} \right)} \right)} \\ $$$${find}\:{the}\:{last}\:{two}\:{digits}\:{of}\:{a}_{\mathrm{23}} \:{and}\:{so}\:{on} \\ $$

Answered by AlagaIbile last updated on 07/Aug/24

$$\:\mathrm{21} \\ $$

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Let-a-1-1-a-2-2-1-a-3-3-2-1-a-4-4-3-2-1-find-the-last-two-digits-of-a-23-and-so-on-

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