Question Number 211634 by BaliramKumar last updated on 15/Sep/24
Answered by golsendro last updated on 15/Sep/24
$$\:\mathrm{x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{3}} }\:=\:\frac{\mathrm{64}+\mathrm{1}}{\mathrm{8}}\:=\:\mathrm{2}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{3}} } \\ $$$$\:\mathrm{y}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{y}^{\mathrm{3}} }\:=\:\frac{\mathrm{729}+\mathrm{1}}{\mathrm{27}}=\:\mathrm{3}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{3}} } \\ $$$$\:\:\mathrm{xy}\:=\:\mathrm{6} \\ $$
Commented by BaliramKumar last updated on 15/Sep/24
$${thanks} \\ $$