Question Number 213861 by BaliramKumar last updated on 19/Nov/24
Answered by A5T last updated on 19/Nov/24
$${cotA}+{cotB}=\frac{\mathrm{1}}{{tanA}}+\frac{\mathrm{1}}{{tanB}}=\frac{{p}}{{tanAtanB}}={q} \\ $$$$\Rightarrow{tanAtanB}=\frac{{p}}{{q}} \\ $$$${cot}\left({A}+{B}\right)=\frac{\mathrm{1}}{{tan}\left({A}+{B}\right)}=\frac{\mathrm{1}−{tanAtanB}}{{tanA}+{tanB}}=\frac{\mathrm{1}−\frac{{p}}{{q}}}{{p}} \\ $$$$\Rightarrow{cot}\left({A}+{B}\right)=\frac{{q}−{p}}{{pq}} \\ $$
Commented by BaliramKumar last updated on 19/Nov/24
$${Thanks} \\ $$