Question Number 214030 by RoseAli last updated on 24/Nov/24
Answered by A5T last updated on 24/Nov/24
$${x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{5}=\mathrm{0} \\ $$$$\Rightarrow\left({x}+\mathrm{1}\right)^{\mathrm{2}} \equiv\mathrm{6}\left({mod}\:\mathrm{10}\right) \\ $$$$\Rightarrow{x}=\mathrm{3},\mathrm{5} \\ $$