Menu Close

Question-214280




Question Number 214280 by Karleepsingh1438 last updated on 03/Dec/24
Commented by JuniorKepler last updated on 03/Dec/24
((25 × 5^2  × t^8  )/(10^3  × t^4 )) = ((25 × 25 × t^4 )/(1000))  = ((5t^4 )/4)
$$\frac{\mathrm{25}\:×\:\mathrm{5}^{\mathrm{2}} \:×\:{t}^{\mathrm{8}} \:}{\mathrm{10}^{\mathrm{3}} \:×\:{t}^{\mathrm{4}} }\:=\:\frac{\mathrm{25}\:×\:\mathrm{25}\:×\:{t}^{\mathrm{4}} }{\mathrm{1000}} \\ $$$$=\:\frac{\mathrm{5}{t}^{\mathrm{4}} }{\mathrm{4}} \\ $$
Answered by Rasheed.Sindhi last updated on 04/Dec/24
((5^2 ×5^2 ×t^8 )/(2^3 ×5^3 ×t^4 ))  ((5^4 ×t^8 )/(2^3 ×5^3 ×t^4 ))  ((5t^(8−4) )/8)  ((5t^4 )/8)
$$\frac{\mathrm{5}^{\mathrm{2}} ×\mathrm{5}^{\mathrm{2}} ×{t}^{\mathrm{8}} }{\mathrm{2}^{\mathrm{3}} ×\mathrm{5}^{\mathrm{3}} ×{t}^{\mathrm{4}} } \\ $$$$\frac{\mathrm{5}^{\mathrm{4}} ×{t}^{\mathrm{8}} }{\mathrm{2}^{\mathrm{3}} ×\mathrm{5}^{\mathrm{3}} ×{t}^{\mathrm{4}} } \\ $$$$\frac{\mathrm{5}{t}^{\mathrm{8}−\mathrm{4}} }{\mathrm{8}} \\ $$$$\frac{\mathrm{5}{t}^{\mathrm{4}} }{\mathrm{8}} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *